y2-y1 /x2-x1
-1-4/ 2-3
m = -5/-1
m = 5
parallel = slope 5
perpendicular slope -1/5
Find the slope of the lines that are (a) parallel lines (b) perpendicular lines to the lines passing through the pair of points (3, 4)(2,-1)
3 answers
slope with the given points
= (-1-4)/2-3) = -5/-1 = 5
so any parallel line has slope 5
any perpendicular line has slope -1/5
= (-1-4)/2-3) = -5/-1 = 5
so any parallel line has slope 5
any perpendicular line has slope -1/5
To get the slope we use the formula:
m = (y2 - y1) / (x2 - x1)
where (x1,y1) and (x2,y2) are the points.
Substituting,
m = (4 - (-1)) / (3 - 2)
m = (4 + 1) / 1
m = 5
(a) Note that parallel lines have equal slope. Thus slope of the parallel line is also equal to 5.
(b) Note that perpendicular lines have negative reciprocal of slope of each other. Thus, the slope of perpendicular line is equal to -1/5.
Hope this helps :3
m = (y2 - y1) / (x2 - x1)
where (x1,y1) and (x2,y2) are the points.
Substituting,
m = (4 - (-1)) / (3 - 2)
m = (4 + 1) / 1
m = 5
(a) Note that parallel lines have equal slope. Thus slope of the parallel line is also equal to 5.
(b) Note that perpendicular lines have negative reciprocal of slope of each other. Thus, the slope of perpendicular line is equal to -1/5.
Hope this helps :3