Find the slope of the line that contains the two points (3,2) and (1,-4).

Question

m = - 3
m = - 1/3 <-- ?
m = 3
m = 1/3

Find the slope of the line that contains the points (-2, 4) and (-4, 6).

m = -1
m = 1 <--
m = - 1/3
m = 1/3

Find the equation of the line that passes through the points (7,4) and (-5,-2)?

y=1/2x-1/2
y=-1/2x-1/2
y=-1/2x+1/2<--
y=1/2x+1/2

Find the equation of the line that passes through the points (1,4) and (2,-8).

y = -3x + 9
y = 6x + 5
y = -12x + 16
y = 12x - 8 <---

Answer 1

Find the slope of the line that contains the two points (3,2) and (1,-4).

slope is ∆y/∆x = (-4-2)/(1-3) = -6/-2 = 3

Find the slope of the line that contains the points (-2, 4) and (-4, 6)

slope is (6-4)/(-4-(-2)) = 2/-2 = -1

>b>Find the equation of the line that passes through the points (7,4) and (-5,-2).

slope is (-2-4)/(-5-7) = -6/-12 = 1/2

the point slope form gives

y-4 = 1/2 (x-7)
y = 1/2 x - 7/2 + 4
y = 1/2 x + 1/2

Find the equation of the line that passes through the points (1,4) and (2,-8).

slope = (-8-4)/(2-1) = -12/1 = -12

y-4 = 12(x-1)
y = 12x - 8
You got that one right.

Looks like you need to be more careful figuring your slopes.

Answer 2

Thank you and yes I honestly do... it's hard for me at least but I do try.