Asked by barb
find the slope of the line, if it exists:
coordinates are (-1,-5), (1,-5)
I am doing something wrong because I either get 5 or if I work it another way I get 0
m= either 5 or 0
Which one is it if any?
x1-x2/y1-y2
Can you please help me through this?
coordinates are (-1,-5), (1,-5)
I am doing something wrong because I either get 5 or if I work it another way I get 0
m= either 5 or 0
Which one is it if any?
x1-x2/y1-y2
Can you please help me through this?
Answers
Answered by
MathMate
The slope of a line through two given points P1(x1,y1) and P2(x2,y2) is given by the expression:
m=(y2-y1)/(x2-x1)
Since y2=y1, so y2-y1=0.
Next we have to check if the slope exists:
(x2-x1)=1-(-1)=2 ≠ 0.
Therefore m=0/2=0.
Note: if y2=y1 and x2=x1, then P1 and P2 are two coincident points, and the slope does not exist, because we cannot define a line through two coincident points.
m=(y2-y1)/(x2-x1)
Since y2=y1, so y2-y1=0.
Next we have to check if the slope exists:
(x2-x1)=1-(-1)=2 ≠ 0.
Therefore m=0/2=0.
Note: if y2=y1 and x2=x1, then P1 and P2 are two coincident points, and the slope does not exist, because we cannot define a line through two coincident points.
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