m = tan θ = ( y2 - y1 ) / ( x2 - x1 )
In this case:
Coordinates of point 1 , x1 = 1 , y1 = - 2
Coordinates of point 2 , x2 = 3 , y1 = 2
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Remark:
( 1 , - 2 ) mean
x coordinate of point 1 , x1 = 1
y coordinate of point 1 , y1 = - 2
( 3 , 2 ) mean
x coordinate of point 2 , x2 = 3
y coordinate of point 2 , y2 = 2
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m = ( y2 - y1 ) / ( x2 - x1 ) =
[ 2 - ( - 2 ) ] / (3 - 1) = ( 2 + 2 ) / 2 = 4 / 2 = 2
find the slope of the line
(1,-2) (3,2)
A. -2
B.2
C.-1/2
D.1/2
2 answers
Thanx so much! :D