Find the slope of graph y = 2×^2+5 at a point p at which x = 1.5

Answer 1

To find the slope of the graph at a point, we need to find the derivative of the equation at that point.

So, taking a derivative of the equation y = 2x^2 + 5, we get:

dy/dx = 4x

Now, at the point where x = 1.5, the slope is:

dy/dx = 4(1.5) = 6

Therefore, the slope of the graph y = 2x^2 + 5 at the point where x = 1.5 is 6.

Answer 2

So, taking a derivative of the equation y = 2x^2 + 5, we get:

dy/dx = 4x

Now, at the point where x = 1.5, the slope is:

dy/dx = 4(1.5) = 6

Therefore, the slope of the graph y = 2x^2 + 5 at the point where x = 1.5 is 6.

Answer 3

Oh it already answered