Find the slope of f(t)= sqrt((1-sin (2t))

Question

a) at point (0,1)
i got -1

b) at origin
i got 1

is this right thanks

Answer 1

f = √(1-sin(2t))
f' = 1/(2√(1-sin(2t))) * -cos(2t) * 2
= -cos(2t)/√(1-sin(2t))

Answer 2

at x=0, that's -1/1 = -1
you are correct

at x=0, f=1, so it makes no sense to ask about f' at the origin.

Answer 3

Thank you!