f = √(1-sin(2t))
f' = 1/(2√(1-sin(2t))) * -cos(2t) * 2
= -cos(2t)/√(1-sin(2t))
Find the slope of f(t)= sqrt((1-sin (2t))
a) at point (0,1)
i got -1
b) at origin
i got 1
is this right thanks
3 answers
at x=0, that's -1/1 = -1
you are correct
at x=0, f=1, so it makes no sense to ask about f' at the origin.
you are correct
at x=0, f=1, so it makes no sense to ask about f' at the origin.
Thank you!