Find the slope of f(t)= sqrt((1-sin (2t))

a) at point (0,1)
i got -1

b) at origin
i got 1

is this right thanks

3 answers

f = √(1-sin(2t))
f' = 1/(2√(1-sin(2t))) * -cos(2t) * 2
= -cos(2t)/√(1-sin(2t))
at x=0, that's -1/1 = -1
you are correct

at x=0, f=1, so it makes no sense to ask about f' at the origin.
Thank you!
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