f '(x) = (-9/5)x^-2 = -9/(5x^2)
f '(1) = -9/5
now you have the slope and a point, use your grade 9 method to find the equation of the line
Find the slope m of the tangent line to the graph of the function at the given point and determine an equation of the tangent line.
f(x) = 9/(5 x) ( at ) \(1,(9/5))
m =
y=
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