y = mx + b
3x + y = 5
3x - 3x + y = -3x + 5
y = -3x + 5
m = -3
y - y1 = m(x -x1)
y - 4 = -3(x - (-1))
y -4 =-3(x+1)
y - 4 = -3x -3
y -4 + 4 = -3x -3 + 4
y = -3x + 1
Find the slope-intercept equation of the line that satisfies the given conditions. Then graph the line.
Contains points P=( -1,4);parallel to the line with equation 3x+y =5
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