Sorry, your answer is not correct. It is a big negative number.
The slope of a line passing between two points P1(x1,y1) and P2(x2,y2) is
m=(y2-y1)/(x2-x1) provided (x2-x1)≠0
I leave it to you to recalculate the slope required. Post your answer for verification if required.
find the slope, if it exists, of the line containing the pair of points
(9,5) and (10,-3)
teh slope m= 1.2
m=(-3+9)/ (10-5)
m=6/5
m=1.2
3 answers
M= (y2-y1)/(x2-x1)
so (-3-5)/(10-9)=-7
so (-3-5)/(10-9)=-7
For -3-5 I get -8.