Find the side of a square whose diagonal is 16√2cm
2 answers
well, the diagonal of a square of side s is s√2, so what do you think?
Use Pythagorean theorem to find the value of a.
a² + b² = c²
The diagonal is the hypotenuse c.
Since a and b are equal, we consider them as a.
a² + a² = c²
2 a² = c²
2 a² = ( 16√2 )²
2 a² = 16² ∙ ( √2 )²
2 a² = 16² ∙ 2
Divide both sides by 2
a² = 16²
a = √16²
a = 16 cm
a² + b² = c²
The diagonal is the hypotenuse c.
Since a and b are equal, we consider them as a.
a² + a² = c²
2 a² = c²
2 a² = ( 16√2 )²
2 a² = 16² ∙ ( √2 )²
2 a² = 16² ∙ 2
Divide both sides by 2
a² = 16²
a = √16²
a = 16 cm