Find the second​, fourth​, and eleventh terms of the sequence described by the rule.​A(n)equalsnegative 4plus​(nminus​1)(6​)Question content area bottomPart 1​A(2​)equalsenter your response here ​(Simplify your​ answer.)

Answer 1

To find the terms of the sequence described by the rule \( A(n) = -4 + (n - 1)(6) \), we can plug in the values of \( n \) for the second, fourth, and eleventh terms.

1. Finding \( A(2) \): \[ A(2) = -4 + (2 - 1)(6) \] \[ = -4 + (1)(6) \] \[ = -4 + 6 \] \[ = 2 \]

2. Finding \( A(4) \): \[ A(4) = -4 + (4 - 1)(6) \] \[ = -4 + (3)(6) \] \[ = -4 + 18 \] \[ = 14 \]

3. Finding \( A(11) \): \[ A(11) = -4 + (11 - 1)(6) \] \[ = -4 + (10)(6) \] \[ = -4 + 60 \] \[ = 56 \]

Summary of Results:

• \( A(2) = 2 \)
• \( A(4) = 14 \)
• \( A(11) = 56 \)

So the values are:

• \( A(2) = 2 \)
• \( A(4) = 14 \)
• \( A(11) = 56 \)