f(x) = e^(−3x) + 5e^(4x)
Note that the derivative of e^x is equal to e^x times the derivative of the exponent with variable x:
d/dx (e^x) = e^x dx
applying this,
f'(x) = -3e^(-3x) + 20e^(4x) : First derivative
f''(x) = 9e^(-3x) + 80e^(4x) : Second derivative
Find the second derivative of the function.
f(x) = e−3x + 5e4x
1 answer
1 answer