The normal to the given plane is [3,2,6]
Since the new plane is perpendicular to the old plane, [3,2,6] must be a direction vector in the new plane.
You can find vector MN, which would be a second direction vector in your new plane.
You now have a point M, and 2 direction vectors.
Find the equation of your new plane using your favourite method.
(let me know what you get)
Find the scalar equation of the plane through the points M(1,2,3) and N(3,2,-1) that is perpendicular to the plane with equation 3x + 2y + 6z +1 = 0.
1 answer