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find the remainder when (x^40 -3) is divided by (x+1)Asked by Lily
Find the remainder when 40^{13} is divided by 81.
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GPT 3.5
To find the remainder when 40^{13} is divided by 81, we can use Euler's theorem.
Since 81 = 3^4, we need to find the remainder of 40^{13} when divided by 3^4.
First, we compute the remainder when 40 is divided by 3:
40 ÷ 3 = 13 remainder 1
Next, we calculate the remainder when 40^{13} is divided by 3^4:
Since 40 mod 3 = 1, we have:
1^{13} mod 3^4 = 1 mod 81 = 1
Therefore, the remainder when 40^{13} is divided by 81 is 1.
Since 81 = 3^4, we need to find the remainder of 40^{13} when divided by 3^4.
First, we compute the remainder when 40 is divided by 3:
40 ÷ 3 = 13 remainder 1
Next, we calculate the remainder when 40^{13} is divided by 3^4:
Since 40 mod 3 = 1, we have:
1^{13} mod 3^4 = 1 mod 81 = 1
Therefore, the remainder when 40^{13} is divided by 81 is 1.
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