dh/dt = 2 t, slope = 0 at t = 0
d^2 h / dt^2 = 2, positive so heading up from there
Find the relative extrema, if any, of the function. Use the Second Derivative Test, if applicable. (If an answer does not exist, enter DNE.)
h(t) = t^2+1/2
relative maximum
relative minimum
1 answer