first, put into descending powers:
3x^3+3x^2-27x = 0
Now factor out 3x, leaving
3x(x^2+x-9) = 0
so, clearly, x=0 is one solution
use the quadratic formula to find the others. You know they are real, since the discriminant is positive.
find the real or imaginary solutions of each equation by factoring.
3x^3+3x^2=27x
*please show work so i can learn how to do this.
1 answer
1 answer