Find the real-number solution of the equation. 3x^7 = 81x^4

I got this far...
3x^7 - 81x^4 = 0
x^4 (3x^3 - 81) = 0

2 answers

3x^7 = 81x^4

divided both sides by 3

x^7 = 27x^4

divided both sides by x^4

x^3 = 27

take the cube root of each side

x=3
or
x = 0

since ....
x&7 - 27x^4 = 0
x^4 (x^3 - 27) = 0
x^4 = 0 or x^3 = 27
x = 0 or x = 3
Similar Questions
  1. Find the number of​ real-number solutions of the equation below.x squared minus 2 x plus 6 equals 0 Question content area
    1. answers icon 3 answers
  2. One of the solutions to the equation x^2+5x^2+10x+50=0is an imaginary number. Which of the following options correctly describes
    1. answers icon 1 answer
    1. answers icon 1 answer
  3. the discriminant of a quadratic equation is -5which answers describes the number and type of solution of the equation? 2 complex
    1. answers icon 1 answer
more similar questions