x = -1 is one root, as you can easily verify by inspection. That means that (x +1) is a factor of the polynomial.
Divide x^3-3x^2+25x+29 by x+1 (using polynomial long division) to get a second order polynomial, from which you can get the other roots easily, using the quadratic formula. They will be complex in this case.
Find the real and complex zeros of the following function.
f(x)=x^3-3x^2+25x+29
1 answer