To find the range of the function \( f(x) = 3x + 7 \) for the given domain \({-2, -1, 0, 1, 2}\), we will calculate \(f(x)\) for each value in the domain.
-
For \(x = -2\): \[ f(-2) = 3(-2) + 7 = -6 + 7 = 1 \]
-
For \(x = -1\): \[ f(-1) = 3(-1) + 7 = -3 + 7 = 4 \]
-
For \(x = 0\): \[ f(0) = 3(0) + 7 = 0 + 7 = 7 \]
-
For \(x = 1\): \[ f(1) = 3(1) + 7 = 3 + 7 = 10 \]
-
For \(x = 2\): \[ f(2) = 3(2) + 7 = 6 + 7 = 13 \]
Now, we have calculated the function values:
- \(f(-2) = 1\)
- \(f(-1) = 4\)
- \(f(0) = 7\)
- \(f(1) = 10\)
- \(f(2) = 13\)
The range of the function for the given domain is \({1, 4, 7, 10, 13}\).
Thus, the correct answer is: \[ {1, 4, 7, 10, 13} \]