Find the range of the function F(x)= definite integral from [-6,x] of sqrt(36-t^2)dt.
[0, 36π]
[0, 18π]***
[-6, 6]
[-6, 0]
2 answers
i know this question has something to do with semicircles and radians. I got the starred answer as my own but I'm not sure if it's correct or how I got there. Help thanks!!
The region is a semi-circle of radius 6, so the area ranges from 0 to 18π
The integral is the area moving from the left side to some point x in [-6,6].
The integral is the area moving from the left side to some point x in [-6,6].
0 answers