2x2 + x + 2y2 + y = 0
2(x2 + x/2) + 2(y2 + y/2) = 0
2(x2 + x/2 + 1/4) + 2(y2 + y/2 + 1/4) - 2(1/4) - 2(1/4) = 0
2(x - 1/2)2 + 2(y - 1/2)2 = 1
(x - 1/2)2 + (y - 1/2)2 = 1/2
Center = (1/2,1/2) radius = 1/√2
find the radius and co-ordinates of the center of the circle: 2x^2+2y^2+x+y=o
2 answers
Rats. Botched it.
2(x2 + x/2 + 1/16) + 2(y2 + y/2 + y/16) - 4(1/16) = 0
2(x + 1/4)2 + 2(y + 1/4)2 = 1/4
(x + 1/4)2 + (y + 1/4)2 = 1/8
center = (-1/4, -1/4)
radius = 1/√8
2(x2 + x/2 + 1/16) + 2(y2 + y/2 + y/16) - 4(1/16) = 0
2(x + 1/4)2 + 2(y + 1/4)2 = 1/4
(x + 1/4)2 + (y + 1/4)2 = 1/8
center = (-1/4, -1/4)
radius = 1/√8