To find the product, we can use the distributive property of multiplication over addition:
(3f–3)(2f+1) = 3f(2f) + 3f(1) – 3(2f) – 3(1)
Simplifying this expression, we get:
6f² + 3f – 6f – 3
Combining like terms, we obtain:
6f² – 3
Therefore, the product of (3f–3)(2f+1) is 6f² – 3.
Find the product. Simplify your answer.
(3f–3)(2f+1)
2 answers
(3f–3)(2f+1)
= 6f^2 + 3f - 6f - 3
= 6f^2 - 3f - 3
or
3(2f^2 - f - 1)
= 6f^2 + 3f - 6f - 3
= 6f^2 - 3f - 3
or
3(2f^2 - f - 1)