r = (6/7) / (3/2) = 4/7
x = (3/2) * (7/4)
y = (6/7) * (4/7)
find the product of x and y if x,3/2,6/7,y are in geometric progression
3 answers
T2=ar =3/2
T3=ar^2 =6/7
ar^2/ar=6/7/3/2
r=4/7
Recall T2=ar
3/2=4/7a
a=21/8
Therefore, x=21/8
T4(y) =ar^3
T4=21/8×(4/7)^3
T4=21/8×64/343
T4=24/49
Therefore y=24/49
Product=21/8 ×24/49
=9/7
T3=ar^2 =6/7
ar^2/ar=6/7/3/2
r=4/7
Recall T2=ar
3/2=4/7a
a=21/8
Therefore, x=21/8
T4(y) =ar^3
T4=21/8×(4/7)^3
T4=21/8×64/343
T4=24/49
Therefore y=24/49
Product=21/8 ×24/49
=9/7
The third and fourth of a g.p are 48 and 142/9 respectively write down the first four terms