To find the product of the polynomials \((2x + 1)(x - 4)\), we can use the distributive property (also known as the FOIL method for binomials).
\[ (2x + 1)(x - 4) = 2x \cdot x + 2x \cdot (-4) + 1 \cdot x + 1 \cdot (-4) \]
Now, we compute each term:
- \(2x \cdot x = 2x^2\)
- \(2x \cdot (-4) = -8x\)
- \(1 \cdot x = x\)
- \(1 \cdot (-4) = -4\)
Now we can combine all these terms:
\[ 2x^2 - 8x + x - 4 \]
Combine like terms:
\[ 2x^2 + (-8x + x) - 4 = 2x^2 - 7x - 4 \]
Thus, the product of the polynomials is:
\[ 2x^2 - 7x - 4 \]
So the coefficients in the form \( ( )x^2 + ( )x + ( ) \) are:
- Coefficient of \(x^2\) is \(2\)
- Coefficient of \(x\) is \(-7\)
- Constant term is \(-4\)
Final answer: \( (2)x^2 + (-7)x + (-4) \)