Find the product of (4x^3 + 2x^2) (6x - 9). Provide your answer in descending order of exponents.

(1 point)

1 answer

To find the product of the polynomials \( (4x^3 + 2x^2)(6x - 9) \), we will use the distributive property (also known as the FOIL method in the case of binomials).

  1. Distribute \( 4x^3 \) to both terms in \( (6x - 9) \): \[ 4x^3 \cdot 6x = 24x^4 \] \[ 4x^3 \cdot (-9) = -36x^3 \]

  2. Distribute \( 2x^2 \) to both terms in \( (6x - 9) \): \[ 2x^2 \cdot 6x = 12x^3 \] \[ 2x^2 \cdot (-9) = -18x^2 \]

  3. Now, combine all the terms we obtained: \[ 24x^4 + (-36x^3 + 12x^3) - 18x^2 \] \[ = 24x^4 + (-36x^3 + 12x^3) - 18x^2 \] \[ = 24x^4 - 24x^3 - 18x^2 \]

  4. Finally, write the expression in descending order of exponents: \[ \boxed{24x^4 - 24x^3 - 18x^2} \]