Find the product of 4+iand 4-i

Answer 1

To find the product of (4+i) and (4-i), we can use the FOIL method:

(4+i) * (4-i) = 4*4 + 4*(-i) + i*4 + i*(-i)
= 16 - 4i + 4i - i^2
= 16 - i^2 (since i^2 = -1)
= 16 - (-1)
= 17

Therefore, the product of (4+i) and (4-i) is 17.