Find the product of 4+I and 4-1

Answer 1

To find the product of (4+I) and (4-I), we can use the formula for the product of two binomials:

(a+b)(a-b) = a^2 - b^2

In this case, a = 4 and b = I. So we have:

(4+I)(4-I) = 4^2 - I^2

Now, we know that I^2 = -1, so we can substitute that in:

(4+I)(4-I) = 16 - (-1)

Simplifying the double negative, we get:

(4+I)(4-I) = 16 + 1

So the product of (4+I) and (4-I) is 17.