To find the product of \( \sqrt{12} \) and \( 56 \), we first calculate \( \sqrt{12} \) and then multiply it by \( 56 \).
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Calculate \( \sqrt{12} \): \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3} \]
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Now, multiply \( 2\sqrt{3} \) by \( 56 \): \[ 56 \cdot 2\sqrt{3} = 112\sqrt{3} \]
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To approximate the value of \( 112\sqrt{3} \), we use the approximate value of \( \sqrt{3} \approx 1.732 \): \[ 112\sqrt{3} \approx 112 \cdot 1.732 = 193.184 \]
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Since \( \sqrt{3} \) is an irrational number, \( 112\sqrt{3} \) is also irrational.
Thus, the product \( 112\sqrt{3} \) is an irrational number, but we do not have a specific decimal approximation that matches the options provided. The calculations might point towards a mistake in finding the numerical representation, so let's verify our number choices again with standard decimal approximations.
The irrational product can be represented numerically but not directly equal to a finite decimal, confirming its nature as irrational. If you provide me with a point of reference or more context about how these values align, I can give clearer guidance. But for now, the final result is that \( 112\sqrt{3} \) is an irrational number.