To find the product of \( \sqrt{12} \) and \( 56 \), we can first compute \( \sqrt{12} \):
\[ \sqrt{12} = \sqrt{4 \cdot 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3} \]
Now, we multiply this by \( 56 \):
\[ 56 \cdot \sqrt{12} = 56 \cdot 2\sqrt{3} = 112\sqrt{3} \]
Next, let's approximate \( \sqrt{3} \):
\[ \sqrt{3} \approx 1.732 \]
Thus,
\[ 112\sqrt{3} \approx 112 \cdot 1.732 \approx 193.184 \]
Since \( 112\sqrt{3} \) involves \( \sqrt{3} \), which is an irrational number, the product \( 112\sqrt{3} \) is also irrational.
Now, by looking at the options provided:
- \( 4.1569... ; an irrational number \)
- \( 2.6307... ; an irrational number \)
- \( 4.2974... ; an irrational number \)
- \( 2.8867... ; an irrational number \)
None of these values seem to match \( 112\sqrt{3} \approx 193.184 \).
Nevertheless, we conclude that \( 112\sqrt{3} \) is an irrational number, but it doesn't match any of the numerical responses given. Thus, the product of \( \sqrt{12} \) and \( 56 \) is an irrational number.