To find the product of (2y-7)(3y+5), we can use the FOIL method:
(2y)(3y) + (2y)(5) + (-7)(3y) + (-7)(5)
= 6y^2 + 10y - 21y - 35
= 6y^2 - 11y - 35
Therefore, the product of (2y-7)(3y+5) is 6y^2 - 11y - 35.
find the product
(2y-7)(3y+5)
1 answer