Find the probability that among six randomly selected people, exactly four of them have brown eyes. Assume that 40% of the population has brown eyes

1 answer

p = .4 so (1-p) = .6
binomial distribution
n = 6
k = 4
C(n,k) = n!/[ k! (n-k)! ]
= 6!/[4!(2!)] = 6*5/ 2 = 15

P(n,k) = 15 * p^k * (1-p)^(n-k)
=15 * .4^4 * .6*2

= .1152