Find the probability of seeing at most 5 dots, but also an odd number of dots when 2 fair dice are rolled.

Answer 1

at most 5 dots --> 2 , 3, 4, 5 dots
11, 12, 21, 22, 23, 32 ---> 6 ways

showing odd number of dots: 3, 5, 7 , 9 , 11

{12, 21, 23, 32, 43, 34 , 54, 45 , 65 , 56}
so we want {at most 5 dots} AND {showing odd sum}
= {12, 21, 23, 32}
or 4 ways

prob(stated event) = 4/36 = 1/9