On a die, 3 numbers are prime (2, 3, 5) and 3 numbers are not prime (1, 4, 6).
Since the chances of rolling a prime each time are the same as those of not rolling a prime each time, we can treat it much like a coin toss.
2 outcomes each roll (Prime or Not Prime), with 10 rolls, gives a total number of possible outcomes of 2^10 = 1024.
In 10 rolls, 3 Primes can occur in 10c3 ways.
Therefore probability is 10c3/(2^10).
Find the probability of getting a prime number thrice by tossing a die 10 times.
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