The probability ofdrawing just one club in the 52 draws = 1/4 * (3/4)^51
The probability of drawing two clubs — which fits the "at least" description — in 52 draws = (1/4)^2 * (3/4)^50
The probability of drawing three clubs in 52 draws = (1/4)^3 * (3/4)^49
Or you could go from the opposite direction, 1 - probability of drawing no clubs.
Does that lead you to a formula?
I hope this helps. Thanks for asking.
FIND THE PROBABILITY OF DRAWING AT LEAST ONE CLUB WHEN YOU DRAW CARDS FROM A STANDAD 52-CARD DECK 52 TIMES; ASSUME YOU REPLACE THE CARD EAC TIMEYOU DRAW, SO THERE ARE ALWAYS 52 CARDS O DRAW FROM. LIST THE APPROPRIE FORMULA, TEN COMPUTE YOUR ANSWER.
2 answers
13/52