The probability of choosing a red marble is the same as the probability of choosing any other marble, assuming all marbles are equally likely to be chosen. Let's say there are 10 marbles in the bag and 4 of them are red.
The probability of choosing a red marble on the first draw is 4/10 or 2/5.
Since the marbles are replaced, the probability of choosing a white marble on the second draw is also 2/5, assuming that there are 3 white marbles remaining in the bag after the first draw out of the original 10.
To find the probability of both events happening, we can multiply the probabilities together:
(2/5) x (2/5) = 4/25 or approximately 0.16.
Therefore, the probability of choosing a red marble, then a white marble if the marbles are replaced is 4/25 or approximately 0.16.
find the probability of choosing a red marble, then a white marble if the marbles are replaced
7 answers
a bag contains 4 white, 3 blue and 5 red marbles find the probability of choosing a red marble, then a white marble if the marbles are replaced
Since the marbles are replaced, the probability of choosing a red marble on the first draw is 5/12, as there are 5 red marbles out of a total of 12 marbles in the bag.
Similarly, the probability of choosing a white marble on the second draw is 4/12, as there are 4 white marbles remaining out of the original 12 marbles in the bag.
To find the probability of both events happening, we can multiply the probabilities together:
(5/12) x (4/12) = 5/54 or approximately 0.093.
Therefore, the probability of choosing a red marble, then a white marble if the marbles are replaced is 5/54 or approximately 0.093.
Similarly, the probability of choosing a white marble on the second draw is 4/12, as there are 4 white marbles remaining out of the original 12 marbles in the bag.
To find the probability of both events happening, we can multiply the probabilities together:
(5/12) x (4/12) = 5/54 or approximately 0.093.
Therefore, the probability of choosing a red marble, then a white marble if the marbles are replaced is 5/54 or approximately 0.093.
better go back to bot-school
(5/12)(4/12)
= 20/144
= 5/36 or appr .139
(5/12)(4/12)
= 20/144
= 5/36 or appr .139
I apologize for my mistake. You are correct. The probability of choosing a red marble, then a white marble if the marbles are replaced is (5/12) x (4/12) = 20/144 = 5/36 or approximately 0.139. Thank you for correcting me.
what about the rest of the answers?????
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