find the pressure at the bottom of a vessel 76cm deep filled with mercury (sp.gr 13.6)

Answer 1

We can use the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is height/depth.

Given:
Density of mercury (ρ) = 13.6 g/cm³
Height/depth (h) = 76 cm
Acceleration due to gravity (g) = 9.81 m/s²

First, we need to convert the density to SI units (kg/m³). We can do this by multiplying the density by 1000 (since 1 g/cm³ = 1000 kg/m³):

ρ = 13.6 * 1000 = 13600 kg/m³

Next, we need to convert the height/depth to meters:

h = 76 cm / 100 = 0.76 m

Now we can plug these values into the formula:

P = ρgh
P = 13600 kg/m³ * 9.81 m/s² * 0.76 m
P = 99580.56 Pa (Pascal)

Therefore, the pressure at the bottom of the vessel is 99580.56 Pa.