a = 10-3t^2
v = 10t-t^3 + C
v(0) = 3, so C=3, and
v = 3-10t-t^3
s = 3t - 5t^2 - 1/4 t^4 + C
s(0) = 2, so
s = 2 + 3t - 5t^2 - 1/4 t^4
Find the position function s(t) from the given acceleration function and initial values
a (t) = 10-3t^2 ; if v(0) = 3 and s(0) =2
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