Find the polar coordinates of (8, –8) for r > 0.

Answer 1

r^2 = 64+64 = 128
r = 8√2

(8,-8) is in IV and tanØ=-1
Ø = 315° or 7π/4

(x,y) ----> (r,Ø)
(8,-8) ---> (8√2 , 7π/4)