Since both parts of f are continuous in their domains, just check to see whether they meet at x=2
16/x^2 = 16/4 = 4 when x=2
3x-2 -> 6-2 = 4 when x->2
Looks continuous to me.
Find the points of discontinuity.
f(x) = { 16/x^2 if x ≥ 2
{ 3x - 2 if x < 2
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