Find the points at which y = f(x) = x8−13x has a global maximum and minimum on the interval 0 ≤ x ≤ 3.7. Round your answers to two decimal places.
Global Maximum:
(x,y) = (,)
Global Minimum:
(x,y) = (,)
3 answers
I just did the previous question for you, do this one the same way,
i cant figure out the global minimum
I will assume your function is
f(x) = x^8 - 13x
f(0) = 0
f(3.7) = 3.7^8 - 13(3.7) = appr. 35077
also f'(x) = 8x^7 - 13 = 0 for local max/min
x^7 = 13/8
x = 1.0718
f(1.0718) = approx -12.2
draw your conclusion following your course's definition of "global minimum"
f(x) = x^8 - 13x
f(0) = 0
f(3.7) = 3.7^8 - 13(3.7) = appr. 35077
also f'(x) = 8x^7 - 13 = 0 for local max/min
x^7 = 13/8
x = 1.0718
f(1.0718) = approx -12.2
draw your conclusion following your course's definition of "global minimum"