f'(x) = 5 - 1/x
for local max/min, set 5-1/x = 0
x =1/5
find f(1/5) for the local max/min
now evaluate
f(.1) , f(2) to find the max/min at the end points.
Find the points at which y = f(x) = 5x−ln(5x) has a global maximum, a global minimum, and a local, non-global maximum on the interval .1 ≤ x ≤ 2. Round your answers to two decimal places.
Global Minimum:
(x,y) = (,)
Global Maximum:
(x,y) = (,)
Local, Non-Global Maximum:
(x,y) = (,)
1 answer