huh? This is just Algebra I. You want to solve
6cosθ = 4 - 2cosθ
8cosθ = 4
cosθ = 1/2
Now you're home free!
Find the point(s) of intersection for the polar curves with equations r = 6 cos θ and r = 4 − 2 cos θ.
a) π/6,-π/6
b) π/3,-π/3
c) π/2,-π/2
d) 0,π
2 answers
I did:
6cosθ= 4 - 2cosθ
For the circle will be 6cosθ is:
r=6cosθ
r^2=6rcosθ
x^2+y^2=6x
but I NEED for the cardioid to get my 2 equations and then I will use my first equation to replace in the second equation with 6x
6cosθ= 4 - 2cosθ
For the circle will be 6cosθ is:
r=6cosθ
r^2=6rcosθ
x^2+y^2=6x
but I NEED for the cardioid to get my 2 equations and then I will use my first equation to replace in the second equation with 6x
5 answers