Find the point closest to the line sqroot(X+1) from the point (3,0).
d = [(x - 3) + (y - 0)]^1/2
d = [(x - 3) + (y)]1/2
Do I now substitute in the equation y = sqroot(X+1) and solve?
3 answers
Yes, and take the derivative and set to zero for the min distance.
You forgot the squares:
d = [(x - 3)^2 + y^2]1/2
It is easier to minimize d^2:
d^2 = (x-3)^2 + y^2
Insert in here y^2 = x+1 and set the derivative of d^2 w.r.t. x equal to zero.
d = [(x - 3)^2 + y^2]1/2
It is easier to minimize d^2:
d^2 = (x-3)^2 + y^2
Insert in here y^2 = x+1 and set the derivative of d^2 w.r.t. x equal to zero.
Thanks both of you.
1 answer