Find the point closest to the line sqroot(X+1) from the point (3,0).

d = [(x - 3) + (y - 0)]^1/2
d = [(x - 3) + (y)]1/2

Do I now substitute in the equation y = sqroot(X+1) and solve?

3 answers

Yes, and take the derivative and set to zero for the min distance.
You forgot the squares:

d = [(x - 3)^2 + y^2]1/2

It is easier to minimize d^2:

d^2 = (x-3)^2 + y^2

Insert in here y^2 = x+1 and set the derivative of d^2 w.r.t. x equal to zero.
Thanks both of you.