To find the perimeter of the shape made up of rectangles and squares, we will add up all the sides.
Given the dimensions you provided:
- 41 cm (two sides)
- 12 cm (two sides)
- 9 cm (one side)
- 11 cm (one side)
We can assume a typical arrangement where we visualize a shape made up of a rectangle (41 cm and 12 cm) and possibly other segments represented by 9 cm and 11 cm sides.
Now, let's calculate the perimeter.
- Start with the lengths:
- 41 cm (two sides)
- 12 cm (two sides)
- 9 cm (two sides, assuming there's a symmetry)
- 11 cm (two sides, assuming there's a symmetry)
In this case, the formula for the perimeter \( P \) of a polygon is: \[ P = \text{sum of all side lengths} \]
Assuming you have a closed shape with four sides of both 41 cm and 12 cm and two sides of 9 cm and 11 cm, we will proceed as follows for the total perimeter.
Let’s assume:
- Two sides of 41 cm: \( 41 + 41 = 82 \)
- Two sides of 12 cm: \( 12 + 12 = 24 \)
- One side of 9 cm: \( 9 \)
- One side of 11 cm: \( 11 \)
Now calculating total: \[ 82 + 24 + 9 + 11 = 126 \]
But be mindful of the arrangement which could cause some sides to be shared thus reducing the overall perimeter. Therefore, if indeed it is just the addition of the lengths listed without any overlap, the total perimeter is: 126 cm
Please confirm any specific arrangement or overlaps to refine this calculation!