P(∆BCE) = 9+12+17 = 38
P(∆ADF) = 15/12 P(∆BCE)
Find the perimeter of the given triangle. Round your answer to the nearest tenth if necessary.
∆ADF, if ∆ADF ∼ ∆BCE, given BC = 17, BE = 9, CE = 12, and DF = 15.
∆BCE is inside of ∆ADF
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