Question

Find the perimeter of rectangle ABCD , with vertices A(1,7) , B(4,7) , C(4,−4) , and D(1,−4)

Answer 1

i dont understand

Answer 2

To find the perimeter of the rectangle, we need to add up the lengths of all four sides.

Using the distance formula, the distance between points A and B is:
AB = √( (4-1)^2 + (7-7)^2 )
AB = √(3^2 + 0^2)
AB = √9
AB = 3

The distance between points B and C is:
BC = √( (4-4)^2 + (-4-7)^2 )
BC = √(0^2 + (-11)^2)
BC = 11

The distance between points C and D is:
CD = √( (1-4)^2 + (-4+4)^2 )
CD = √((-3)^2)
CD = 3

The distance between points D and A is:
DA = √( (1-1)^2 + (-4-7)^2 )
DA = √(0^2 + (-11)^2)
DA = 11

Now, add up all the distances to find the perimeter:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 11 + 3 + 11
Perimeter = 28

Therefore, the perimeter of rectangle ABCD is 28 units.

Answer 3

I apologize for the confusion. Let me explain it in a different way:

To find the perimeter of a rectangle, you need to add up the lengths of all four sides.

Given that the vertices of the rectangle are A(1,7), B(4,7), C(4,-4), and D(1,-4), we can calculate the lengths of each side:

1. Distance between points A(1,7) and B(4,7):
Length of AB = 4 - 1 = 3 units

2. Distance between points B(4,7) and C(4,-4):
Length of BC = 7 - (-4) = 11 units

3. Distance between points C(4,-4) and D(1,-4):
Length of CD = 4 - 1 = 3 units

4. Distance between points D(1,-4) and A(1,7):
Length of DA = 7 - (-4) = 11 units

Now, add up the lengths of all four sides to find the perimeter:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 11 + 3 + 11
Perimeter = 28 units

Therefore, the perimeter of rectangle ABCD is 28 units.