Find the perimeter of a square with a side length of 212−−√

. Your answer must be in simplest radical form.(1 point)
Responses

323–√
32 square root of 3

163–√
16 square root of 3

812−−√
8 square root of 12

848−−√

1 answer

To find the perimeter of a square, you can use the formula:

\[ \text{Perimeter} = 4 \times \text{side length} \]

Given the side length of the square is \( \sqrt{212} \):

\[ \text{Perimeter} = 4 \times \sqrt{212} \]

Now, let's simplify \( \sqrt{212} \):

\[ \sqrt{212} = \sqrt{4 \times 53} = \sqrt{4} \times \sqrt{53} = 2\sqrt{53} \]

Now substituting this back into the perimeter calculation:

\[ \text{Perimeter} = 4 \times (2\sqrt{53}) = 8\sqrt{53} \]

Thus, the perimeter of the square in simplest radical form is:

\[ \boxed{8\sqrt{53}} \]

Regarding the given options, there does not seem to be a direct match to our answer, but the perimeter we calculated is indeed \(8\sqrt{53}\). Please provide clarity on the comparison of our answer with the provided choices.