The longest side of a right triangle is the hypotenuse, c in
a^2 + b^2 = c^2
so
a^2 + 20^2 = 52^2
a^2 = 2704 - 400 = 2304
a = 48
perimeter = 48 + 20 + 52 = 120 mm
area = (1/2)48(20) = 480 mm^2
Find the perimeter and area of a right triangle if the shortest side is 20 mm. and the longest side is 52 mm.
3 answers
oh thank you so much!! i was totally off...
You are welcome :)