f' = 4x^2
f = 4/3 x^3 + C
Since f(-1)=3,
(4/3)(-1)+C = 3
C = 13/3
So,
f(x) = 4/3 x^3 + 13/3
do the other one in like wise.
Find the particular solution that satisfies the differential equation and the initial conditions.
F'(x) = 4x^2 f (-1)=3
F'(t)=10t-12t^3 f (3)=2
1 answer