Find the particular solution that satisfies the differential equation and the initial conditions.

F'(x) = 4x^2 f (-1)=3

F'(t)=10t-12t^3 f (3)=2

1 answer

f' = 4x^2
f = 4/3 x^3 + C

Since f(-1)=3,
(4/3)(-1)+C = 3
C = 13/3

So,
f(x) = 4/3 x^3 + 13/3

do the other one in like wise.