Find the parametric equations for the line through the point P = (5, -1, -3) that is perpendicular to the plane 4x−4y+0z=1.

Use "t" as your variable, t = 0 should correspond to P, and the velocity vector of the line should be the same as the standard normal vector of the plane.

x =

y =

z =

3 answers

t = (x-5)/4 = (y+1)/-4
x = 4t + 5
y = -4t - 1
as well as
z = -3
oh, yeah -- what he said.